The average annual and hourly salaries for extraction workers helpers in the state of Iowa are shown in Table 1 and Table 2, respectively. The comparison of the salary statistics of extraction workers helpers amongst Iowa metropolitan areas is shown in Table 3. The salary statistics are based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2017 and published in April 2018 .
|Percentile Bracket||Average Annual Salary|
|10th Percentile Wage||$16,990|
|25th Percentile Wage||$18,790|
|50th Percentile Wage||$30,360|
|75th Percentile Wage||$36,920|
|90th Percentile Wage||$40,510|
Table 1 shows the average annual salary for extraction workers helpers in Iowa in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $40,510. The median (50th percentile) annual salary is $30,360. The average annual salary for the bottom 10 percent is $16,990.
The table and chart below show the trend of the median salary of extraction workers helpers from 2012 to 2017.
|Year||Median Salary||Yearly Growth||5-Year Growth|