The annual and hourly salary statistics of property, real estate managers in Springfield, Ohio are shown in Table 1 and Table 2, respectively. The wage statistics of property, real estate managers in Springfield is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2017 and published in April 2018 .
|Percentile Bracket||Average Annual Salary|
|10th Percentile Wage||$35,820|
|25th Percentile Wage||$46,510|
|50th Percentile Wage||$58,310|
|75th Percentile Wage||$72,710|
|90th Percentile Wage||$88,940|
Table 1 shows the average annual salary for property, real estate managers in Springfield, Ohio in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $88,940. The median (50th percentile) annual salary is $58,310. The average annual salary for the bottom 10 percent earners is $35,820.
The table and chart below show the trend of the median salary of property, real estate managers from 2012 to 2017.
|Year||Median Salary||Yearly Growth||5-Year Growth|
From Table 3 we note that with a median annual salary of $58,310, Springfield is the highest paying city for property, real estate managers in state of Ohio, followed by Toledo (median annual salary $55,860). In comparison, the median annual salary of property, real estate managers in Springfield is 4.2 percent (4.2%) higher than that in Toledo.
|Cities/Areas||Median Annual Salary|
|Southern Ohio nonmetropolitan area|| |
|Other Ohio nonmetropolitan area|| |
|West Northwestern Ohio nonmetropolitan area|| |
|Eastern Ohio nonmetropolitan area|| |
See also: Top paying jobs in Springfield, Ohio.