The average annual and hourly salaries for other health diagnosing and treating practitioners in the state of Texas are shown in Table 1 and Table 2, respectively. The comparison of the salary statistics of other health diagnosing and treating practitioners amongst Texas metropolitan areas is shown in Table 3. The salary statistics are based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2017 and published in April 2018 .
|Percentile Bracket||Average Annual Salary|
|10th Percentile Wage||$48,280|
|25th Percentile Wage||$57,600|
|50th Percentile Wage||$66,680|
|75th Percentile Wage||$86,600|
|90th Percentile Wage||$111,560|
Table 1 shows the average annual salary for other health diagnosing and treating practitioners in Texas in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $111,560. The median (50th percentile) annual salary is $66,680. The average annual salary for the bottom 10 percent is $48,280.
The table and chart below show the trend of the median salary of other health diagnosing and treating practitioners from 2012 to 2017.
|Year||Median Salary||Yearly Growth||5-Year Growth|
Table 3 shows the median annual salary of other health diagnosing and treating practitioners in some Texas cities and metropolitan areas. We note that the median annual salary of other health diagnosing and treating practitioners in state of Texas ranges from $52,350 to $84,180. The highest paying area for other health diagnosing and treating practitioners in Texas is San Antonio-New Braunfels with a median annual salary of $84,180. The second highest paying city/area in Texas State is Fort Worth-Arlington (mean annual salary $68,390). The lowest paying area is Austin-Round Rock-San Marcos with a median annual salary of $52,350.
|Cities/Areas||Median Annual Salary|
|San Antonio-New Braunfels|| |
|Fort Worth-Arlington|| |
|Houston-Sugar Land-Baytown|| |
|Dallas-Fort Worth-Arlington|| |
|Austin-Round Rock-San Marcos|| |