The average annual and hourly salaries for surveyors in the state of Texas are shown in Table 1 and Table 2, respectively. The comparison of the salary statistics of surveyors amongst Texas metropolitan areas is shown in Table 3. The salary statistics are based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2017 and published in April 2018 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $32,710 |
| 25th Percentile Wage | $40,680 |
| 50th Percentile Wage | $56,800 |
| 75th Percentile Wage | $78,450 |
| 90th Percentile Wage | $97,840 |
Table 1 shows the average annual salary for surveyors in Texas in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $97,840. The median (50th percentile) annual salary is $56,800. The average annual salary for the bottom 10 percent is $32,710.
The table and chart below show the trend of the median salary of surveyors from 2012 to 2017.
| Year | Median Salary | Yearly Growth | 5-Year Growth |
|---|---|---|---|
| 2017 | $56,800 | 0.85% | 10.14% |
| 2016 | $56,320 | -0.09% | - |
| 2015 | $56,370 | 6.99% | - |
| 2014 | $52,430 | 2.65% | - |
| 2013 | $51,040 | 0.00% | - |
| 2012 | $51,040 | - | - |
Table 3 shows the median annual salary of surveyors in some Texas cities and metropolitan areas. We note that the median annual salary of surveyors in state of Texas ranges from $30,130 to $78,950. The highest paying area for surveyors in Texas is Central Texas nonmetropolitan area with a median annual salary of $78,950. The second highest paying city/area in Texas State is San Antonio-New Braunfels (mean annual salary $71,960). The lowest paying area is Brownsville-Harlingen with a median annual salary of $30,130.
