The annual salary statistics of information security analysts in Palm Bay-Melbourne-Titusville, Florida is shown in Table 1. The wage statistics of information security analysts in Palm Bay-Melbourne-Titusville is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
Percentile Bracket | Average Annual Salary |
---|---|
10th Percentile Wage | $56,720 |
25th Percentile Wage | $72,740 |
50th Percentile Wage | $101,260 |
75th Percentile Wage | $135,690 |
90th Percentile Wage | $159,350 |
Table 1 shows the average annual salary for information security analysts in Palm Bay-Melbourne-Titusville, Florida in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $159,350. The median (50th percentile) annual salary is $101,260. The average annual salary for the bottom 10 percent earners is $56,720.
The table and chart below show the trend of the median salary of information security analysts from 2012 to 2018.
Year | Median Salary | Yearly Growth | 6-Year Growth |
---|---|---|---|
2018 | $101,260 | 14.85% | 24.89% |
2017 | $86,220 | 6.72% | - |
2016 | $80,430 | -6.60% | - |
2015 | $85,740 | 14.77% | - |
2014 | $73,080 | -2.23% | - |
2013 | $74,710 | -1.81% | - |
2012 | $76,060 | - | - |
From Table 3 we note that with a median annual salary of $101,260, Palm Bay-Melbourne-Titusville is the highest paying city for information security analysts in state of Florida, followed by Orlando-Kissimmee-Sanford (median annual salary $95,910). In comparison, the median annual salary of information security analysts in Palm Bay-Melbourne-Titusville is 5.3 percent (5.3%) higher than that in Orlando-Kissimmee-Sanford.