The annual salary statistics of insurance sales agents in Sebring, Florida is shown in Table 1. The wage data of insurance sales agents in Sebring is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $29,350 |
| 25th Percentile Wage | $37,350 |
| 50th Percentile Wage | $37,350 |
| 75th Percentile Wage | $48,530 |
| 90th Percentile Wage | $74,850 |
Table 1 shows the average annual salary for insurance sales agents in Sebring, Florida in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $74,850. The median (50th percentile) annual salary is $37,350. The average annual salary for the bottom 10 percent earners is $29,350.
The table and chart below show the trend of the median salary of insurance sales agents from 2012 to 2022.
| Year | Median Salary | Yearly Growth | 5-Year Growth |
|---|---|---|---|
| 2022 | $37,350 | -16.71% | -29.42% |
| 2021 | $43,590 | 3.88% | - |
| 2020 | $41,900 | -12.36% | - |
| 2019 | $47,080 | 2.06% | - |
| 2018 | $46,110 | -4.84% | - |
| 2017 | $48,340 | - | - |
From Table 3 we note that with a median annual salary of $37,350, Sebring is the lowest paying city for insurance sales agents in state of Florida, following city of Miami-Miami Beach-Kendall (median annual salary of $62,380). Also we note that in comparison, the annual salary of insurance sales agents in Sebring is about 40.1 percent (40.1%) lower than that of the highest paying city Miami-Miami Beach-Kendall.