The annual salary statistics of set and exhibit designers in Miami-Miami Beach-Kendall, Florida is shown in Table 1. The wage information of set and exhibit designers in Miami-Miami Beach-Kendall is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $25,690 |
| 25th Percentile Wage | $28,220 |
| 50th Percentile Wage | $35,360 |
| 75th Percentile Wage | $60,730 |
| 90th Percentile Wage | $77,960 |
Table 1 shows the average annual salary for set and exhibit designers in Miami-Miami Beach-Kendall, Florida in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $77,960. The median (50th percentile) annual salary is $35,360. The average annual salary for the bottom 10 percent earners is $25,690.
The table and chart below show the trend of the median salary of set and exhibit designers from 2012 to 2017.
| Year | Median Salary | Yearly Growth | 5-Year Growth |
|---|---|---|---|
| 2017 | $35,360 | -37.42% | 38.24% |
| 2016 | $48,590 | 5.25% | - |
| 2015 | $46,040 | 13.44% | - |
| 2014 | $39,850 | 40.25% | - |
| 2013 | $23,810 | 8.27% | - |
| 2012 | $21,840 | - | - |
From Table 3 we note that with a median annual salary of $35,360, Miami-Miami Beach-Kendall is the lowest paying city for set and exhibit designers in state of Florida, following city of Fort Lauderdale-Pompano Beach-Deerfield Beach (median annual salary of $53,720). In comparison, the median annual salary of set and exhibit designers in Miami-Miami Beach-Kendall is 34.2 percent (34.2%) lower than that in the highest paying city Fort Lauderdale-Pompano Beach-Deerfield Beach.
| Cities/Areas | Median Annual Salary |
|---|---|
| Fort Lauderdale-Pompano Beach-Deerfield Beach | |
| Miami-Fort Lauderdale-Pompano Beach | |
| North Port-Bradenton-Sarasota | |
| Tampa-St Petersburg-Clearwater | |
| Orlando-Kissimmee-Sanford | |
| Miami-Miami Beach-Kendall |