The annual salary statistics of sewers, hand in Jacksonville, Florida is shown in Table 1. The wage information of sewers, hand in Jacksonville is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $22,070 |
| 25th Percentile Wage | $25,250 |
| 50th Percentile Wage | $29,810 |
| 75th Percentile Wage | $34,970 |
| 90th Percentile Wage | $37,980 |
Table 1 shows the average annual salary for sewers, hand in Jacksonville, Florida in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $37,980. The median (50th percentile) annual salary is $29,810. The average annual salary for the bottom 10 percent earners is $22,070.
The table and chart below show the trend of the median salary of sewers, hand from 2012 to 2019.
| Year | Median Salary | Yearly Growth | 7-Year Growth |
|---|---|---|---|
| 2019 | $29,810 | 29.32% | 29.32% |
| 2015 | $21,070 | 7.02% | - |
| 2014 | $19,590 | 5.56% | - |
| 2013 | $18,500 | -13.89% | - |
| 2012 | $21,070 | - | - |
From Table 3 we note that with a median annual salary of $29,810, Jacksonville is the highest paying city for sewers, hand in state of Florida, followed by Miami-Fort Lauderdale-Pompano Beach (median annual salary $24,250). In comparison, the median annual salary of sewers, hand in Jacksonville is 18.7 percent (18.7%) higher than that in Miami-Fort Lauderdale-Pompano Beach.
| Cities/Areas | Median Annual Salary |
|---|---|
| Jacksonville | |
| Miami-Fort Lauderdale-Pompano Beach | |
| Tampa-St Petersburg-Clearwater |