The annual salary statistics of team assemblers in Iowa City, Iowa is shown in Table 1. The wage statistics of team assemblers in Iowa City is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2019 and published in April 2020 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $21,770 |
| 25th Percentile Wage | $25,920 |
| 50th Percentile Wage | $31,350 |
| 75th Percentile Wage | $38,290 |
| 90th Percentile Wage | $46,520 |
Table 1 shows the average annual salary for team assemblers in Iowa City, Iowa in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $46,520. The median (50th percentile) annual salary is $31,350. The average annual salary for the bottom 10 percent earners is $21,770.
The table and chart below show the trend of the median salary of team assemblers from 2012 to 2016. Note that there is no salary data for some years between 2012 and 2019.
| Year | Median Salary | Growth | 2-Year Growth |
|---|---|---|---|
| 2016 | $31,350 | -7.08% | -4.11% |
| 2015 | $33,570 | 2.77% | - |
| 2014 | $32,640 | - | - |
From Table 3 we note that the median annual salary of $31,350 in Iowa City is in the middle of salary range for team assemblers in state of Iowa. In comparison, the annual salary of team assemblers in Iowa City is 14.5 percent (14.5%) lower than that in the highest paying Waterloo-Cedar Falls and 6.9 percent (6.9%) higher than that in the lowest paying Northeast Iowa nonmetropolitan area.