The annual salary statistics of team assemblers in Bloomington-Normal, Illinois is shown in Table 1. The wage statistics of team assemblers in Bloomington-Normal is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2019 and published in April 2020 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $26,010 |
| 25th Percentile Wage | $37,210 |
| 50th Percentile Wage | $53,130 |
| 75th Percentile Wage | $57,810 |
| 90th Percentile Wage | $60,620 |
Table 1 shows the average annual salary for team assemblers in Bloomington-Normal, Illinois in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $60,620. The median (50th percentile) annual salary is $53,130. The average annual salary for the bottom 10 percent earners is $26,010.
The table and chart below show the trend of the median salary of team assemblers from 2012 to 2013. Note that there is no salary data for some years between 2012 and 2019.
| Year | Median Salary | Growth | 1-Year Growth |
|---|---|---|---|
| 2013 | $53,130 | 26.14% | 26.14% |
| 2012 | $39,240 | - | - |
From Table 3 we note that with a median annual salary of $53,130, Bloomington-Normal is the highest paying city for team assemblers in state of Illinois, followed by Decatur (median annual salary $43,520). In comparison, the median annual salary of team assemblers in Bloomington-Normal is 18.1 percent (18.1%) higher than that in Decatur.