The annual salary statistics of sewers, hand in Cincinnati-Middletown, Ohio is shown in Table 1. The wage data of sewers, hand in Cincinnati-Middletown is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $23,210 |
| 25th Percentile Wage | $25,830 |
| 50th Percentile Wage | $28,390 |
| 75th Percentile Wage | $31,000 |
| 90th Percentile Wage | $35,910 |
Table 1 shows the average annual salary for sewers, hand in Cincinnati-Middletown, Ohio in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $35,910. The median (50th percentile) annual salary is $28,390. The average annual salary for the bottom 10 percent earners is $23,210.
The table and chart below show the trend of the median salary of sewers, hand from 2012 to 2019.
| Year | Median Salary | Yearly Growth | 7-Year Growth |
|---|---|---|---|
| 2019 | $28,390 | 0.07% | 6.94% |
| 2018 | $28,370 | 6.56% | - |
| 2014 | $26,510 | 2.49% | - |
| 2013 | $25,850 | -2.21% | - |
| 2012 | $26,420 | - | - |
From Table 3 we note that with a median annual salary of $28,390, Cincinnati-Middletown is the lowest paying city for sewers, hand in state of Ohio, following city of Columbus (median annual salary of $31,720). Compared with the highest paying city Columbus, the median annual salary of sewers, hand in Cincinnati-Middletown is 10.5 percent (10.5%) lower.
| Cities/Areas | Median Annual Salary |
|---|---|
| Columbus | |
| West Northwestern Ohio nonmetropolitan area | |
| Toledo | |
| Cleveland-Elyria-Mentor | |
| Cincinnati-Middletown |