The annual salary statistics of demonstrators and product promoters in Brownsville-Harlingen, Texas is shown in Table 1. The wage statistics of demonstrators and product promoters in Brownsville-Harlingen is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $18,070 |
| 25th Percentile Wage | $23,770 |
| 50th Percentile Wage | $29,730 |
| 75th Percentile Wage | $36,090 |
| 90th Percentile Wage | $37,170 |
Table 1 shows the average annual salary for demonstrators and product promoters in Brownsville-Harlingen, Texas in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $37,170. The median (50th percentile) annual salary is $29,730. The average annual salary for the bottom 10 percent earners is $18,070.
The table and chart below show the trend of the median salary of demonstrators and product promoters from 2012 to 2021.
| Year | Median Salary | Yearly Growth | 9-Year Growth |
|---|---|---|---|
| 2021 | $29,730 | 6.29% | 18.06% |
| 2018 | $27,860 | 7.36% | - |
| 2017 | $25,810 | 5.62% | - |
| 2016 | $24,360 | 0.00% | - |
| 2012 | $24,360 | - | - |
From Table 3 we note that the median annual salary of $29,730 in Brownsville-Harlingen is in the middle of salary range for demonstrators and product promoters in state of Texas. In comparison, the annual salary of demonstrators and product promoters in Brownsville-Harlingen is 49.0 percent (49.0%) lower than that in the highest paying Midland and 34.3 percent (34.3%) higher than that in the lowest paying Amarillo.