The annual salary statistics of industrial production managers in Brownsville-Harlingen, Texas is shown in Table 1. The wage information of industrial production managers in Brownsville-Harlingen is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2019 and published in April 2020 [1].
Percentile Bracket | Average Annual Salary |
---|---|
10th Percentile Wage | $63,750 |
25th Percentile Wage | $77,830 |
50th Percentile Wage | $111,700 |
75th Percentile Wage | $150,190 |
90th Percentile Wage | $185,970 |
Table 1 shows the average annual salary for industrial production managers in Brownsville-Harlingen, Texas in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $185,970. The median (50th percentile) annual salary is $111,700. The average annual salary for the bottom 10 percent earners is $63,750.
The table and chart below show the trend of the median salary of industrial production managers from 2012 to 2019.
Year | Median Salary | Yearly Growth | 7-Year Growth |
---|---|---|---|
2019 | $111,700 | 16.73% | 33.60% |
2018 | $93,010 | -11.89% | - |
2017 | $104,070 | 8.74% | - |
2016 | $94,970 | 19.80% | - |
2015 | $76,170 | 11.24% | - |
2014 | $67,610 | 2.29% | - |
2013 | $66,060 | -12.28% | - |
2012 | $74,170 | - | - |
From Table 3 we note that the median annual salary of $111,700 in Brownsville-Harlingen is in the middle of salary range for industrial production managers in state of Texas. In comparison, the annual salary of industrial production managers in Brownsville-Harlingen is 18.2 percent (18.2%) lower than that in the highest paying Beaumont-Port Arthur and 44.9 percent (44.9%) higher than that in the lowest paying McAllen-Edinburg-Mission.