The annual salary statistics of dental hygienists in Los Alamos County, New Mexico is shown in Table 1. The wage information of dental hygienists in Los Alamos County is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $67,350 |
| 25th Percentile Wage | $73,080 |
| 50th Percentile Wage | $83,310 |
| 75th Percentile Wage | $108,890 |
| 90th Percentile Wage | $122,210 |
Table 1 shows the average annual salary for dental hygienists in Los Alamos County, New Mexico in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $122,210. The median (50th percentile) annual salary is $83,310. The average annual salary for the bottom 10 percent earners is $67,350.
The table and chart below show the trend of the median salary of dental hygienists from 2012 to 2017.
| Year | Median Salary | Yearly Growth | 5-Year Growth |
|---|---|---|---|
| 2017 | $83,310 | -3.04% | -3.04% |
| 2016 | $85,840 | -8.78% | - |
| 2015 | $93,380 | -0.82% | - |
| 2014 | $94,150 | 3.10% | - |
| 2013 | $91,230 | 5.91% | - |
| 2012 | $85,840 | - | - |
From Table 3 we note that with a median annual salary of $83,310, Los Alamos County is the second highest paying city for dental hygienists in state of New Mexico, following the highest paying city Santa Fe (median annual salary of $92,240). Compared with Santa Fe, the median annual salary of dental hygienists in Los Alamos County is 9.7 percent (9.7%) lower.