The annual salary statistics of dental hygienists in Santa Fe, New Mexico is shown in Table 1. The wage data of dental hygienists in Santa Fe is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2022 and published in April 2023 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $81,920 |
| 25th Percentile Wage | $86,030 |
| 50th Percentile Wage | $92,240 |
| 75th Percentile Wage | $98,440 |
| 90th Percentile Wage | $102,170 |
Table 1 shows the average annual salary for dental hygienists in Santa Fe, New Mexico in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $102,170. The median (50th percentile) annual salary is $92,240. The average annual salary for the bottom 10 percent earners is $81,920.
The table and chart below show the trend of the median salary of dental hygienists from 2012 to 2018.
| Year | Median Salary | Yearly Growth | 6-Year Growth |
|---|---|---|---|
| 2018 | $92,240 | -2.25% | -11.18% |
| 2017 | $94,320 | 5.73% | - |
| 2016 | $88,920 | 2.90% | - |
| 2015 | $86,340 | 22.43% | - |
| 2014 | $66,970 | -3.00% | - |
| 2013 | $68,980 | -48.67% | - |
| 2012 | $102,550 | - | - |
From Table 3 we note that with a median annual salary of $92,240, Santa Fe is the highest paying city for dental hygienists in state of New Mexico, followed by Los Alamos County (median annual salary $83,310). In comparison, the median annual salary of dental hygienists in Santa Fe is 9.7 percent (9.7%) higher than that in Los Alamos County.