The annual salary statistics of lodging managers in Palm Bay-Melbourne-Titusville, Florida is shown in Table 1. The wage information of lodging managers in Palm Bay-Melbourne-Titusville is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2019 and published in April 2020 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $42,630 |
| 25th Percentile Wage | $48,080 |
| 50th Percentile Wage | $66,880 |
| 75th Percentile Wage | $107,380 |
| 90th Percentile Wage | $153,180 |
Table 1 shows the average annual salary for lodging managers in Palm Bay-Melbourne-Titusville, Florida in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $153,180. The median (50th percentile) annual salary is $66,880. The average annual salary for the bottom 10 percent earners is $42,630.
The table and chart below show the trend of the median salary of lodging managers from 2012 to 2019.
| Year | Median Salary | Yearly Growth | 7-Year Growth |
|---|---|---|---|
| 2019 | $66,880 | -3.05% | 4.68% |
| 2018 | $68,920 | 9.49% | - |
| 2017 | $62,380 | -2.20% | - |
| 2016 | $63,750 | 9.90% | - |
| 2015 | $57,440 | 30.19% | - |
| 2014 | $40,100 | 8.23% | - |
| 2013 | $36,800 | -73.23% | - |
| 2012 | $63,750 | - | - |
From Table 3 we note that with a median annual salary of $66,880, Palm Bay-Melbourne-Titusville is the second highest paying city for lodging managers in state of Florida, following the highest paying city Miami-Fort Lauderdale-Pompano Beach (median annual salary of $68,120). Compared with Miami-Fort Lauderdale-Pompano Beach, the median annual salary of lodging managers in Palm Bay-Melbourne-Titusville is 1.8 percent (1.8%) lower.