The annual salary statistics of lodging managers in Brownsville-Harlingen, Texas is shown in Table 1. The wage information of lodging managers in Brownsville-Harlingen is based on the national compensation survey conducted by the U.S. Bureau of Labor Statistics in 2019 and published in April 2020 [1].
| Percentile Bracket | Average Annual Salary |
|---|---|
| 10th Percentile Wage | $32,690 |
| 25th Percentile Wage | $35,860 |
| 50th Percentile Wage | $43,000 |
| 75th Percentile Wage | $56,060 |
| 90th Percentile Wage | $61,000 |
Table 1 shows the average annual salary for lodging managers in Brownsville-Harlingen, Texas in 5 percentile scales. The average annual salary for the 90th percentile (the top 10 percent of the highest paid) is $61,000. The median (50th percentile) annual salary is $43,000. The average annual salary for the bottom 10 percent earners is $32,690.
The table and chart below show the trend of the median salary of lodging managers from 2012 to 2019.
| Year | Median Salary | Yearly Growth | 7-Year Growth |
|---|---|---|---|
| 2019 | $43,000 | 10.58% | -26.09% |
| 2018 | $38,450 | 0.49% | - |
| 2017 | $38,260 | -13.36% | - |
| 2016 | $43,370 | -6.64% | - |
| 2015 | $46,250 | -3.65% | - |
| 2014 | $47,940 | -26.93% | - |
| 2013 | $60,850 | 10.90% | - |
| 2012 | $54,220 | - | - |
From Table 3 we note that the median annual salary of $43,000 in Brownsville-Harlingen is in the middle of salary range for lodging managers in state of Texas. In comparison, the annual salary of lodging managers in Brownsville-Harlingen is 37.2 percent (37.2%) lower than that in the highest paying El Paso and 30.9 percent (30.9%) higher than that in the lowest paying Lubbock.